Find the Errors in the following programs.
#include <iostream.h>
void main ()
{
int i = 0;
i = i+1;
cout << i << "";
/*comment\*//i=i+1;
cout << i;
}
There are a few errors in the provided program:
1. Incorrect header file inclusion: The header file for
input/output operations in C++ is `<iostream>` instead of
`<iostream.h>`. Update the include statement to `#include
<iostream>`.
2. Improper `main()` function declaration: The correct
declaration for the `main()` function in C++ is `int main()`, not `void
main()`. Change the function declaration to `int main()`.
3. Missing namespace qualification: Since you are using
standard C++ library functions like `cout`, you need to specify the `std`
namespace. Add `using namespace std;` after the include statement or prefix the
`cout` statements with `std::`.
4. Invalid comment syntax: The comment syntax
`/*comment\*//` is not valid in C++. The correct syntax for a single-line
comment is `//`. Remove the invalid comment.
Here's the corrected code:
```cpp
#include <iostream>
int main()
{
int i = 0;
i = i + 1;
std::cout << i << "";
// Comment
i = i + 1;
std::cout << i;
return 0;
}
```
These corrections should resolve the errors in the program.
#include <iostream.h>
void main ()
{
short i=2500, j=3000;
cout >> "i + j =" >> -
(i+j);
}
There are a few errors in the code you provided:
1. Incorrect header file inclusion: The correct header file
for input/output operations in C++ is `<iostream>`, not
`<iostream.h>`. Update the include statement to `#include
<iostream>`.
2. Improper `main()` function declaration: The correct
declaration for the `main()` function in C++ is `int main()`, not `void
main()`. Change the function declaration to `int main()`.
3. Incorrect stream operator: The output stream operator in
C++ is `<<`, not `>>`. Change `cout >>` to `cout <<`
for outputting data.
4. Incorrect usage of stream insertion operator: The correct
syntax to output a string literal is `cout << "i + j ="`, not
`cout >> "i + j ="`.
5. Invalid negation operation: In the expression `- (i+j)`,
the parentheses are unnecessary. To negate the result of `(i+j)`, simply use
`-i-j` without the parentheses.
Here's the corrected code:
```cpp
#include <iostream>
int main()
{
short i = 2500, j = 3000;
std::cout << "i + j = "
<< -i - j;
return 0;
}
```
These corrections should resolve the errors in the code.
What will happen when you run the following
program.
#include <iostream.h>
void main()
{
int i=10, j=5;
int modResult=0;
int divResult=0;
modResult = i%j;
count << modResult <<
"";
divResult = i/modResult;
cout << divResult;
}
There are a couple of errors in the code you provided, which
would result in compilation errors. Here are the issues:
1. Incorrect header file inclusion: The correct header file
for input/output operations in C++ is `<iostream>`, not
`<iostream.h>`. Update the include statement to `#include
<iostream>`.
2. Improper `main()` function declaration: The correct
declaration for the `main()` function in C++ is `int main()`, not `void
main()`. Change the function declaration to `int main()`.
3. Invalid output stream object: The correct output stream
object in C++ is `std::cout`, not `count`. Update `count` to `std::cout`.
Here's the corrected code:
#include <iostream>
int main()
{
int i = 10, j = 5;
int modResult = 0;
int divResult = 0;
modResult = i % j;
std::cout << modResult <<
"";
divResult = i / modResult;
std::cout << divResult;
return 0;
}
When you run the corrected code, it will output the values of `modResult` and `divResult`. However, there is a potential issue with division by zero if the remainder (`modResult`) happens to be zero. In such a case, a runtime error will occur. To avoid this, you may want to add a check to ensure that `modResult` is non-zero before performing the division operation.
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